Optimal. Leaf size=129 \[ \frac{3 a^3 \sin ^5(c+d x)}{5 d}-\frac{7 a^3 \sin ^3(c+d x)}{3 d}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{a^3 \sin (c+d x) \cos ^5(c+d x)}{6 d}+\frac{23 a^3 \sin (c+d x) \cos ^3(c+d x)}{24 d}+\frac{23 a^3 \sin (c+d x) \cos (c+d x)}{16 d}+\frac{23 a^3 x}{16} \]
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Rubi [A] time = 0.134471, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {3791, 2633, 2635, 8} \[ \frac{3 a^3 \sin ^5(c+d x)}{5 d}-\frac{7 a^3 \sin ^3(c+d x)}{3 d}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{a^3 \sin (c+d x) \cos ^5(c+d x)}{6 d}+\frac{23 a^3 \sin (c+d x) \cos ^3(c+d x)}{24 d}+\frac{23 a^3 \sin (c+d x) \cos (c+d x)}{16 d}+\frac{23 a^3 x}{16} \]
Antiderivative was successfully verified.
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Rule 3791
Rule 2633
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \cos ^6(c+d x) (a+a \sec (c+d x))^3 \, dx &=\int \left (a^3 \cos ^3(c+d x)+3 a^3 \cos ^4(c+d x)+3 a^3 \cos ^5(c+d x)+a^3 \cos ^6(c+d x)\right ) \, dx\\ &=a^3 \int \cos ^3(c+d x) \, dx+a^3 \int \cos ^6(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^4(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^5(c+d x) \, dx\\ &=\frac{3 a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}+\frac{a^3 \cos ^5(c+d x) \sin (c+d x)}{6 d}+\frac{1}{6} \left (5 a^3\right ) \int \cos ^4(c+d x) \, dx+\frac{1}{4} \left (9 a^3\right ) \int \cos ^2(c+d x) \, dx-\frac{a^3 \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{d}-\frac{\left (3 a^3\right ) \operatorname{Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,-\sin (c+d x)\right )}{d}\\ &=\frac{4 a^3 \sin (c+d x)}{d}+\frac{9 a^3 \cos (c+d x) \sin (c+d x)}{8 d}+\frac{23 a^3 \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac{a^3 \cos ^5(c+d x) \sin (c+d x)}{6 d}-\frac{7 a^3 \sin ^3(c+d x)}{3 d}+\frac{3 a^3 \sin ^5(c+d x)}{5 d}+\frac{1}{8} \left (5 a^3\right ) \int \cos ^2(c+d x) \, dx+\frac{1}{8} \left (9 a^3\right ) \int 1 \, dx\\ &=\frac{9 a^3 x}{8}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{23 a^3 \cos (c+d x) \sin (c+d x)}{16 d}+\frac{23 a^3 \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac{a^3 \cos ^5(c+d x) \sin (c+d x)}{6 d}-\frac{7 a^3 \sin ^3(c+d x)}{3 d}+\frac{3 a^3 \sin ^5(c+d x)}{5 d}+\frac{1}{16} \left (5 a^3\right ) \int 1 \, dx\\ &=\frac{23 a^3 x}{16}+\frac{4 a^3 \sin (c+d x)}{d}+\frac{23 a^3 \cos (c+d x) \sin (c+d x)}{16 d}+\frac{23 a^3 \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac{a^3 \cos ^5(c+d x) \sin (c+d x)}{6 d}-\frac{7 a^3 \sin ^3(c+d x)}{3 d}+\frac{3 a^3 \sin ^5(c+d x)}{5 d}\\ \end{align*}
Mathematica [A] time = 0.206919, size = 73, normalized size = 0.57 \[ \frac{a^3 (2520 \sin (c+d x)+945 \sin (2 (c+d x))+380 \sin (3 (c+d x))+135 \sin (4 (c+d x))+36 \sin (5 (c+d x))+5 \sin (6 (c+d x))+1380 d x)}{960 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.121, size = 143, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ({a}^{3} \left ({\frac{\sin \left ( dx+c \right ) }{6} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{16}}+{\frac{5\,c}{16}} \right ) +{\frac{3\,{a}^{3}\sin \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \cos \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) }+3\,{a}^{3} \left ( 1/4\, \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) +3/8\,dx+3/8\,c \right ) +{\frac{{a}^{3} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{2}+2 \right ) \sin \left ( dx+c \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.05069, size = 193, normalized size = 1.5 \begin{align*} \frac{192 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} a^{3} - 5 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} - 60 \, d x - 60 \, c - 9 \, \sin \left (4 \, d x + 4 \, c\right ) - 48 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3} - 320 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} a^{3} + 90 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3}}{960 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.70349, size = 230, normalized size = 1.78 \begin{align*} \frac{345 \, a^{3} d x +{\left (40 \, a^{3} \cos \left (d x + c\right )^{5} + 144 \, a^{3} \cos \left (d x + c\right )^{4} + 230 \, a^{3} \cos \left (d x + c\right )^{3} + 272 \, a^{3} \cos \left (d x + c\right )^{2} + 345 \, a^{3} \cos \left (d x + c\right ) + 544 \, a^{3}\right )} \sin \left (d x + c\right )}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32461, size = 173, normalized size = 1.34 \begin{align*} \frac{345 \,{\left (d x + c\right )} a^{3} + \frac{2 \,{\left (345 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{11} + 1955 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 4554 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 5814 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 3165 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 1575 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{6}}}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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